if the line x/a+y/b =1 be a tangent to xy =c square then
Answers
Answered by
0
Given: x/a+y/b =1 and curves are x = ct and y = c/t
To find: value of a and b?
Solution:
- Now we have given xy = c²
- Let tangent at point (x1, y1) be: xy1 + yx1 = 2c²
- At general, let x1 = ct and y1 = c/t and put it in above equation, we get:
x(c/t) + y(ct) = 2c²
x/t + yt = 2c
- So the slope of tangent is: -(coeff of x) / coeff of y
m = -(1/t) / t
m = -1/t² < 0
- Now given line is x/a + y/b = 1 is tangent for xy = c², but slope of tangent should always be less that zero.
- So m = -1/a / 1/b < 0
-b/a < 0
b/a > 0
- Now there becomes two cases: either both are greater than 0 or both are less than 0.
- So value of a>0 and b>0 or a<0 and b<0.
Answer:
So value of a>0 and b>0 or a<0 and b<0.
Similar questions