If the line y=3x+k is tangent to the parabola y2=4x then the value of K is
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2x=k+3y
Putting this in y
2
=6x
y
2
=3(k+3y)⇒y
2
−9y−3k=0
For getting 1 value of y as the line TOUCHES the parabola
We should put the Discriminant of the Quadratic Equation D=0
Hence, 9
2
+12k=0⇒k=
12
−81
=
4
−27
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