If the line y=mx bisects the angle between the lines ax^2+2hxy+by^2=0 then m is a root of the quadratic equation
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hx^2+(a−b)x−h=0
Equation of bisectors of the pair of straight lines ax^2+2hxy+by^2=0 is
h(x^2−y^2)−(a−b)xy=0==>>(1)
Since y=mx is given to be the bisector of the pair of straight lines, then the line will satisfy the equation (1)
Then we get,
h(1−m^2)−(a−b)m=0
hm^2+(a−b)m−h=0
So m satisfies the equation
hx^2 +(a−b)x−h=0.
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