if the linear momentum of a body is increased by 50%, its KE will increase by:
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Answer:
If the initial momentum is p
0
, the initial kinetic energy is K
0
=
2m
p
0
2
When momentum is increased by 50 %, the momentum becomes p=p
0
+(p
0
×
100
50
)=(3/2)p
0
Now kinetic energy, K=
2m
p
2
=(9/4)×(p
0
2
/2m)=(9/4)K
0
Thus the percentage increased in kinetic energy =
K
0
K−K
0
×100=[(9/4)−1]100=125 %
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