Question

if the linear momentum of a body is increased by 50% then by what percentage will its kinetic energy increase​

Answer 1

Explanation:

K

$ke = \frac{ {p}^{2} }{2m}$

it is seen that kinetic energy is directly proportional to square of the momentum

∆K.E/K.E (%)= 2(∆p/p) ×100

$2 \times \frac{50}{100} \times 100 = 5 \times 100\%$

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