If the linear momentum of the body increases by 20% , what will be the percentage increase in KE of
body?
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If momentum of a body increases by 20%, then the percentage increase in its kinetic energy is
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Correct option is
B
44
We have,
K.E.=
2m
P
2
ΔK.E. =
2m
P
f
2
-
2m
P
i
2
=
2m
(
5
6P
)
2
-
2m
P
2
=
50m
36P
2
−25P
2
=
50m
11P
2
Now,
% Change =
KE
i
ΔKE
=
2m
P
2
50m
11P
2
×100
=
25
11
×100
=44%
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