Question

If the lines 2x+y-3=0 5x+ky-3=0 and 3x-y-2=0 are concurrent find the value of k

Answer 1

Step-by-step explanation:

2x+y=3

3x-y=2

x=1,y=1

since line are concorence when line are

passing by same point so by solve any two any satisfied other

5+k-3=0

k=2

Answer 2

Answer:

Hlo mate here's your answer hope it helps

2x + y - 3 =0 ———(1)

5x + ky - 3 =0———(2)

3x - y - 2 =0————(3)

By solving (1) & (3) using elimination method

3x - y = 2 ——(3)

2x + y = 3——(1)

____________

x + 0 = 1

& y = 1

by substituting x = 1 and y =1 in (2)

5(1) + k(1) =3

5+k = 3

k = 3-5

=-2

k = -2.