If the lines 3+2−2=0 2+5+1=0 are parallel, then the value of k will be
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3x + 2ky - 2 = 0 … (1)
2x + 5y + 1 = 0 … (2)
Now, convert 1 and 2 into y = mx + c form where m is the slope.
for 1,
y = (-3/2k)x + (1/k)
for 2,
y = (-2/5)x - (1/5)
So now for both lines to be parallel, (-3/2k) must be equal to (-2/5)
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