Math, asked by shweta6686, 3 months ago

If the lines 3x+2y_7=0& 6x-ky+28=0 are parallel then the value of k is​

Answers

Answered by seemaanvi
0

Step-by-step explanation:

3X - 2Y - 7 = 0 ----------(1)

And,

6X + KY = 11

6X + KY - 11 = 0 -----------(2)

These equations are of the form A1X+ B1Y + C1 and A2X + B2Y + C2.

Where,

A1 = 3 , B1 = -2 and C1 = -7

And,

A2 = 6 , B2 = K and C2 = -11

Therefore,

A1/A2 = 3/6 = 1/2 , B1/B2 = -2/K and C1/C2 = 7/11.

A1/A2 # B1/B2

1/2 # -2/K

K # - 4

Hence,

K has real values, except -4.

please note: #is used for not equal to

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