If the lines 5x + 3y + 2 = 0 and 3x - k y + 6 = 0 are perpendicular to each other then value of k is -----.
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The value of k is 5.
Given:
The lines 5x + 3y + 2 = 0 and 3x - k y + 6 = 0 are perpendicular to each other.
To Find:
The value of k.
Solution:
WKT;
Slope of line = (−coefficient of y/coefficient of x)
For the equation 5x+3y+2 = 0
Slope = -5/3
For the equation 3x-ky+6
Slope = 3/k
As the lines are perpendicular, the product of their slopes=−1
=> (-5/3)x(3/k) = -1
=> -5/k = -1
=> k = 5
Hence, the value of k = 5.
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