If the lines given by 2x+2ky=2 and 2x+5y+1=0 are parallel,then the value of k is
Answers
Answered by
1
Answer:
Condition for the lines to be parallel is
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here the equations are
3x+2ky=2 and 2x+5y+1=0
So, a
1
=3,b
1
=2k,c
1
=−2 and a
2
=2,b
2
=5,c
2
=1
∴
a
2
a
1
=
2
3
,
b
2
b
1
=
5
2k
and
c
2
c
1
=
1
−2
=−2
∴
5
2k
=
2
3
∴k=
4
15
Answered by
1
Answer:
Condition for the lines to be parallel is
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here the equations are
3x+2ky=2 and 2x+5y+1=0
So, a
1
=3,b
1
=2k,c
1
=−2 and a
2
=2,b
2
=5,c
2
=1
∴
a
2
a
1
=
2
3
,
b
2
b
1
=
5
2k
and
c
2
c
1
=
1
−2
=−2
∴
5
2k
=
2
3
∴k=
4
15
Similar questions