if the lines given by 2x+ky=1 and 3x+6y=7 are parallel, then find the value of k.
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Answer:
answer is 4
Step-by-step explanation:
to satisfy that lines are parallel a1/a2=b1/b2not equal to c1/c2
so,2/3=k/6not equal to 1/7
so,2/3=k/6
12=3k
k=12/3
k=4.
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