Question

If the lines given by 3x+ 2ky = 2 and 2x+5y+1=0 are parallel parallel , then find value of k.
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Answer 1

Answer:

15/4

Step-by-step explanation:

Suppose that we have to parallel lines 

a1x+b1y+c1=0 & a2x+b2y+c2=0

 then,ratio of coefficient of x and y are equal i.e.  a2a1=b2b1.

Now, according to given equations

3x+2ky=2

2x+5y+1=0

compairing coeffient  of x& y and applying rule,

23=52k

⇒4k=15

So value of k=15./4

Answer 2

Answer:

3x+2ky-2=0; 2x+5y+1=0

compare the equations with general form

a1x+b1y+C1=0 and a2x+b2y+C2=0 we get

a1= 3 ; b1= 2k C1= -2. and a2= 2;b2= 5; C2= 1

the lines are parallel so

a1/a2= b1/b2

3/2= 2k/5

(3/2)*5 =2k

15/2= 2k

15/4= k