Question

If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel, then find value of k.​

Answer 1

Thanks for your question...

Your required answer ;

• $\frac{15}{4}$

Given :

• 3x + 2ky = 2
• 2x + 5y = -1

Condition :

• They are parallel lines

To find :

• Value of K

Solution :

For parallel lines :

$\frac{a1}{a2} = \frac{b1}{b2} \: \: is \: not \: equal \: to \: \: \frac{c1}{c2}$

Here ,

• a1 = 3
• a2 = 2
• b1 = 2k
• b2 = 5

Now ,

$= = > \frac{3}{2} = \frac{2k}{5} \\ \\ = = > 15 = 4k \\ \\ = = > k = \frac{15}{4}$

Brainliest Please

Answer 2

Step-by-step explanation:

Thanks for your question...

Your required answer ;

\frac{15}{4}

4

15

Given :

3x + 2ky = 2

2x + 5y = -1

Condition :

They are parallel lines

To find :

Value of K

Solution :

For parallel lines :

\frac{a1}{a2} = \frac{b1}{b2} \: \: is \: not \: equal \: to \: \: \frac{c1}{c2}

a2

a1

=

b2

b1

isnotequalto

c2

c1

Here ,

a1 = 3

a2 = 2

b1 = 2k

b2 = 5

Now ,

\begin{gathered} = = > \frac{3}{2} = \frac{2k}{5} \\ \\ = = > 15 = 4k \\ \\ = = > k = \frac{15}{4} \end{gathered}

==>

2

3

=

5

2k

==>15=4k

==>k=

4

15

Brainliest Please.