Math, asked by aman5958, 7 months ago

If the lines given by 3x+2ky=2 and 6x+8y=4 are coincide , then the value of k is​

Answers

Answered by aarohisoral
0

Answer:

K=2

Step-by-step explanation:

The common is 1/2

I hope it will help you

Answered by Anonymous
0

Answer:

k=4

Step-by-step explanation:

3x+2ky=2=a1x+b1x+c1=0

6x+8y=4=a2x+b2x+c2=0

FOR COINCIDE OR INFINITE SOLUTION

 \frac{a1}{a2}  =  \frac{b1}{b2}  =  \frac{c1}{c2}

3x/6x=2ky/8y=2/4

 \frac{1}{2}  =  \frac{2 \times 4y}{8y}  =  \frac{1}{2}

 \frac{1}{2}  =  \frac{1}{2}  =  \frac{1}{2}

therefore k=4

mark as brainliest please

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