Question

If the lines given by 4x + 3ky = 5 and 3x + 7y + 2 - 0 are parallel, then the value of k is:​

Answer 1

Answer:

The value of k is $\frac{28}{9}$

Step-by-step explanation:

We know that,

lines $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ are parallel if $\frac{a_1}{a_2}=\frac{b_1}{b_2}$

Now,

since lines $4x+3ky=5$ and $3x+7y+2=0$ are parallel

$\therefore \frac{4}{3}=\frac{3k}{7}\\\Rightarrow 9k=28\\\Rightarrow k=\frac{28}{9}$