Question

if the lines given by 5x+ky+7=0 and 2x+y -3=0 are parallel then find the value of k
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Answer 1

Given ,

The two given lines 5x + ky + 7 = 0 and 2x + y - 3 = 0 are parallel

We know that , if two lines $\tt a_{1}x + b_{1}y + c_{1} = 0$ and$\tt a_{2} x+ b_{2}y + c_{2}= 0$ are parallel , then

$\boxed{ \tt{ \frac{ a_{1} }{a_{2}} = \frac{ b_{1} }{b_{2}} ≠ \frac{ c_{1} }{c_{2}} }}$

Thus ,

5/2 = k/1

5 = 2k

k = 5/2

Therefore , the value of k is 5/2

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Answer 2

Answer:

$\huge{ \bold{ \mathfrak{ \boxed{ \star{ \mathtt{ \purple{answer}{} }{} }{} }{} }{} }{} }{}$

Question:-

if the lines given by 5x+ky+7=0 and 2x+y -3=0 are parallel then find the value of k

Answer:-

Given :-

• The two Given lines 5x+ky+7= 0

and 2x+y-3 = 0 are parallel

Solution:-

• a1x+ b1y + c1 = 0 and we also know
• a2x + b2y +c2 = 0 are parallel

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a1/a2 = b1/b2 ≠ c1/c2

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And Thus we Get the answer,....

• 5/2 = k/1

• 5 = 2k

• so, hence k = 5/2

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