Question

If the lines given by the equations 3x + 5ky = 4 and 2x + 6y + 9 = 0 are parallel, then the value of k is​

Answer 1

Step-by-step explanation:

Condition for the lines to be parallel is

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Here the equations are

3x+2ky=2 and 2x+5y+1=0

So, a

1

=3,b

1

=2k,c

1

=−2 and a

2

=2,b

2

=5,c

2

=1

∴

a

2

a

1

=

2

3

,

b

2

b

1

=

5

2k

and

c

2

c

1

=

1

−2

=−2

∴

5

2k

=

2

3

∴k=

4

15

Answer 2

Answer:

Condition for the lines to be parallel is

a2a2a

= b2 b1

= c2 c1

Here the equations are

3x+2ky=2 and 2x+5y+1=0

So, a

1=3,b 1

=2k,c 1

=−2 and a 2

=2,b 2

=5,c 2=1

∴ a 2a 1

= 23 , b2 b1

= 52kand c2 c1c

= 1−2

=−2

∴ 52k

= 23

∴k= 415

Step-by-step explanation:

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