If the lines given by3x + 2ky = 22 2x + 5y + 1 = 0 are parallel, then the value of k is
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Answer:
given:
3x+2ky=2
=>2ky=-3x+2
=>y=(-3/2k)x+(1/k)
°slope(m1)=(-3/2k)
also,
2x+5y+1=0
=>5y=-2x-1
=>y=(-2/5)x-(1/5)
°slope(m2)=(-2/5)
since, lines are parallel
therefore, m1=m2
that is, (-3/2k)=(-2/5)
this applies:
on further solving:
{k=15/4}✓
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