If the lines of regression yon x is 8x –10y+66 = 0 and x on y is
40x –18y-214= 0 The value of variance of x is 9. The standard deviation of x
is
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To find given regression equation in such a way that the coefficient of dependent variable is less than one at least in one equation.
so, 8x+10y=−66⇒10y=66+8x⇒y=1066+108x
That is byx=8/10=0.8
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