if the lines passing through the points (a, 4) and (-3, -2) passes through the origin the find a
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Answer:
Y-y1 = (y2-y1)/ x2-x1 × (x-x1)
Y-(-2)= (-2-4)÷(-3-a)×(x-(-3))
Y+2= -6÷(-3-a)×( x+3)
Now above line passes through origin
Means (x,y)=(0,0) x=0,y=0
0+2 = -6÷(-3-a)×(3)
2= -18÷(-3-a)
(-3-a)= -9
-a= -9+3
-a= -6
A=6
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