If the lines represented by the equation 6{{x}^{2}}+41xy-7{{y}^{2}}=0
make angles \alpha
and \beta
with x-axis, then \tan \alpha .\tan \beta
=
A) - 6/7 B) 6/ 7 C) 7/6 D) - 7/6
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Do u have a photo of that question it is difficult to read and understand.
Answered by
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Answer:-6/7
Step-by-step explanation:
6x²+41xy-7y²=0
6x²+42xy-xy-7y²=0
6x(x+7y)-y(x+7y)=0
(6x-y)(x+7y)=0
M¹=6 & M²= -1/7
Therefore;
M1M2=6*-1/7
Tan(alpha)*Tan(beta)= -6/7
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