Math, asked by Harsh102005, 9 months ago

if the lines represented by the equation ax+4y+5=0 and ax+12y+c=0 are coincident then find the values of a and c

plz help me guys... please ​

Answers

Answered by rdevi5627
0

Step-by-step explanation:

Answer:

k=6

Step-by-step explanation:

\begin{lgathered}3x + 4y + 2 = 0 \\ multiplying \: both \: side \: by \: 3 \\ 9x + 12y + 6 = 0 \\ as(0 \times 3 = 0) \\ let \: it \: be \: equation \: 1 \\ 9x + 12y + k = 0 \: \\ let \: it \: be \: equation \: 2 \\ \\ from \: equation \: 1 \: and \: 2 \\ 9x + 12y + 6 = 9x + 12y + k \\now \: as \: 9x \: and \: 12y \: cancelled \: out \\ we \: get \: k = 6\end{lgathered}

3x+4y+2=0

multiplyingbothsideby3

9x+12y+6=0

as(0×3=0)

letitbeequation1

9x+12y+k=0

letitbeequation2

fromequation1and2

9x+12y+6=9x+12y+k

nowas9xand12ycancelledout

wegetk=6

Similar questions