if the lines represented by the equation ax+4y+5=0 and ax+12y+c=0 are coincident then find the values of a and c
plz help me guys... please
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Step-by-step explanation:
Answer:
k=6
Step-by-step explanation:
\begin{lgathered}3x + 4y + 2 = 0 \\ multiplying \: both \: side \: by \: 3 \\ 9x + 12y + 6 = 0 \\ as(0 \times 3 = 0) \\ let \: it \: be \: equation \: 1 \\ 9x + 12y + k = 0 \: \\ let \: it \: be \: equation \: 2 \\ \\ from \: equation \: 1 \: and \: 2 \\ 9x + 12y + 6 = 9x + 12y + k \\now \: as \: 9x \: and \: 12y \: cancelled \: out \\ we \: get \: k = 6\end{lgathered}
3x+4y+2=0
multiplyingbothsideby3
9x+12y+6=0
as(0×3=0)
letitbeequation1
9x+12y+k=0
letitbeequation2
fromequation1and2
9x+12y+6=9x+12y+k
nowas9xand12ycancelledout
wegetk=6
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