if the lines representing linear equations 2x-1y+3=0and 6x-3y=k are coincide, then the value of "k" (a) -3 (b) -9 (c) 3 (d) 9
Answers
Answer:
The value of k is 9.
Option d)
Step-by-step-explanation:
The given linear equations are
2x - y + 3 = 0 - - - ( 1 ) &
6x - 3y = k - - - ( 2 )
We have to find the value of k.
Now,
2x - y + 3 = 0 - - - ( 1 )
Comparing with ax + by + c = 0, we get,
- a₁ = 2
- b₁ = - 1
- c₁ = 3
Also,
6x - 3y = k - - - ( 2 )
Comparing with ax + by + c = 0, we get,
- a₂ = 6
- b₂ = - 3
- c₂ = k
We know that,
For two coincident lines,
∴ The value of k is 9.
The given linear equations are
2x - y + 3 = 0 _____(1) &
6x - 3y = k ____(2)
We have to find the value of k.
Now,
2x - y + 3 = 0 ____(1)
Comparing with ax + by + c = 0, we get,
a₁ = 2
b₁ = - 1
c₁ = 3
Also,
6x - 3y = k ___(2)
Comparing with ax + by + c = 0, we get,
a₂ = 6
b₂ = - 3
c₂ = -k
We know that,
For two coincident lines,
a₁/a₂ = b₁/b₂ = c₁/c₂
b₁/b₂ = c₁/c₂
so ,
-1/-3 = 3/-k
k = 3 × -3 = -9
- value of k = -9