If the lines x-3y=10 and kx+6y-1=0 are parallel, then the value of 'k' is what
Answers
Answered by
19
Answer: -2
Step-by-step explanation:For a line ax+by=c, slope is equal to -a/b.
For parallel lines, slopes should be same.
Slope of x-3y=10 is 1/3.
Slope of kx+6y=1 is -k/6
So 1/3=-k/6
k=-2
Answered by
5
Answer:
-2 is the correct answer of this question
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