If the lines x + y + 1 = 0, x – y + 1 = 0 are two diameters of a circle passing through (1,1) then equation of the circle is
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x+y+1=0. equ 1
x-y+1=0. equ 2
by sloving these two equ,we get
x+y+1=0
x-y+1=0
2x+2=0
x=-1
by changing the sign,
x+y+1=0
-x+y-1=0
2y=0
y=0
there fore (x,y)=(-1,0)
these points passes through tha point (1,1)
by two points slope form
x-x1/x2-x1 =y-y1/y2-y1
x+1/1+1 =y-0/1-0
x+1/2 =y/1
x+1=2y
x-2y+1=0
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