If the lines x+y = 6 and x + 2y = 4 are diameters of the circle which passes through the points (2,6) then find its equation .
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Solution :- Here centre will be the point of intersection of the diameter , i.e ,,C(8,-2)
Also , the centre passes through the point P(2,6) . the radius is CP = 10
Hence, the required equation is
(x -8)² +(y + 2)² = 10²
or, x² + y² - 16x + 4y - 32 = 0
________________________
Also , the centre passes through the point P(2,6) . the radius is CP = 10
Hence, the required equation is
(x -8)² +(y + 2)² = 10²
or, x² + y² - 16x + 4y - 32 = 0
________________________
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4
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