Question

. If the lines x + y + u = 0 and λx-5y–5=0 are identical then λ + u is​

Answer 1

Answer:

-4

Step-by-step explanation:

in line x+y+u = 0

a1 = coefficient of x = 1

b1 = coefficient of y = 1

c1 = constant term = u

In line hx - 5y - 5 =0

a2 = h (used in place of lemda)

b2 = -5

c2 = -5

for lines to be identical

a1/a2 = b1/b2 = c1/c2

1/h = 1/-5 = u/-5

this gives

h= -5, u = 1

hence, h+u

= -5+1

= -4

Answer 2

Answer:

-4

Step-by-step explanation:

identical is nothing but coincides

so given lines are x+y+μ=0 and λx-5y-5=0

so condition of coincides is

a1/a2=b1/b2=c1/c2

a1=1,a2=λ,b1=1,b2= -5,c1=μ,c2= -5

so, 1/λ=1/-5=μ/-5

λ= -5 and μ=1

there fore, λ+μ= -5+1

= -4.