Question

If the list price of a toy is reduced by rupees 2, a person can buy 2 toys more for rupees 360. Find the original price of the toy.
PLEASE GIVE THE ANSWER STEP BY STEP.
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PLEASE HELP ME.
IT'S VERY URGENT.

Answer 1

let the no of toys be x and price of each toy be y
therefore, xy = 360
and x=360/y  {eg -1}
2nd condition
(x+2)(y-2)=360
xy + 2y - 2x - 4 = 360
2y - 2(360/y) - 4 = 0  { since xy=360 & from eq 1}
- 4y -720 = 0
- 2y - 360 =0
- 20y +18y -360 =0
y(y-20) +18(y-20) = 0
(y+18)(y-20)=0
therefore y= -18 or y = 20
in this case y=20 since price of quantity cannot e in negative
therefore the original price of toy is 20 rupees

Done☺

Answer 2

SOLUTION :  

Let the original price of the book be ₹ x.

Number of books bought for ₹ 360 = 360/x  

Reduced list price of the book = ₹ (x - 2)

Number of books bought for ₹ 360 = 360/(x - 2)

A.T .Q

360/(x - 2) - 360/x = 2

360[1/(x -2) - 1/x ] = 2

[1/(x -2) - 1/x ] = 2/360

[x - (x - 2)] /x(x - 2) = 1/180

[By taking LCM]

(x - x + 2)/x² - 2x = 1/180

2/x² - 2x = 1/180

x² - 2x = 2 × 180

x² - 2x = 360

x² - 2x  - 360 = 0

x² - 20x + 18x - 360 = 0

[By middle term splitting]

x(x - 20) + 18(x - 20) = 0

(x - 20) (x + 18) = 0

(x - 20) = 0  or  (x + 18) = 0

x = 20 or x = - 18  

Since, the price of the book can't be negative, so x ≠ - 18  

Therefore , x = 20  

Hence, the original  price of the book is ₹ 20.

HOPE THIS ANSWER WILL HELP YOU….