Question

if the load is increased twice for the same area of material then the stress valve will? ​

Answer 1

Answer:

Stress in second case = 2×stress in first case

Explanation:

Let first the load is $F_1$ and area is $A_1$

We know that stress is given by $stress=\frac{force}{area}$

So $stress_{in\ first\ case}=\frac{F_1}{A_1}$----------eqn 1

Now in second case load is increased to twice and area remains same

So $F_2=2F_1$ and $A_2=A_1$

$stress_{in\ second\ case}=\frac{2F_1}{A_1}$---------eqn 2

From equation 1 and 2 it is clear that

Stress in second case = 2×stress in first case