Question

if the logarithm of 27 is 6, what is the base of the logarithm?​

Answer 1

Answer:

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suppose the base is x

$log_{x}(27)$

now we can rewrite this as ,

log (27)/log(x) = 6

log (27)= 6log(x)

log (27)= log(x⁶)

therefore ,

27= x⁶

x= √(3) ≈ 1.73..

thank u!

Answer 2

Step-by-step explanation:

$if \: {a}^{b} = c \\ then \: \: \: log_{a}c = b$

Let base of logarithm be x

$log_{x}27 = 6 \\ {x}^{6} = 27 \\ x = \sqrt[6]{27} \\ x = \sqrt{3} = 1.73205(approx)$