Question

If the longest wavelength in Balmer series of he+ is 9x/5 then the shortest wavelength of H atom in Lymann series

Answer 1

the shortest wave length of Lyman series of H atom is x, then the wave length of the first line Balmer series of H atom will be 1) 9x/52) 36x/53) 5x/94) 5x/36Explanation please..Thank You

one year ago

Answers : (1)

 

The wave no. of any series is given by;



where 109678 is a constant,lets say = ;

and,the series starts from n1 to n2;

 

Here,x is the wavelength for the last line(shortest wavelength) in lyman series,

therefore,n​1=1 to n​2=(infinity)​;

    ​(1/x)=​​[(1/1) – ​(1/)]    =    ​(​1 - 0) = 

    ​  =​ 1/x              

 

For wavelength of first line of balmer series,

n​1=2 to n​2=3  ​;lets say the wavelength to be found be = ;​



Substituting the value



Ans(2)

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