If the loop track has a radius of 6 meters, approximately how fast must the car
be going at the top to stay on the track?
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Q w এর t y u I o p(my answer is car be going at the top to stay on the track)
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Answer:
8 m/s (approx.)
Explanation:
Given that,
r = 6 m and
g =9.8 m/s2
We know,
v^2 = rg [v^2 =v square]
=6*9.8
v=√58.8
v=7.668
=8 m/s (approx.)
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