Question

if the loss of weight of a body when immersed in water is 50N what is its weight in water .its weight in air is 180N​

Answer 1

Explanation:

Weight difference =

150-100 = 50 N = Buoyant force of water

Buoyant Force in water(Fb) = density of water x g x volume of body(Vb)

50 = 1000 x 9.81 x Vb

Vb = 50/9810 cubic meter

Now, in air

Weight of body = mg = 150 N

Mass of body,m = 150/9.81 Kg

So, 

Density of body = m/ Vb

= 150/9.81 ÷ 50/9810

= 3000 kg per cubic meter

Specific gravity of body = density of body ÷ density of water

= 3000 ÷ 1000

Specific gravity of body = 3.

Answer 2

Answer:

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