Question

If the lower and upper limits of a class are 10 and 40 respectively, the mid points of the class is

Answer 1

Step-by-step explanation:

Mid point=(Upper limit +Lower limit)/2

=(40+10)/2

=50/2

=25

Answer 2

Answer:

The midpoint of the given class is 25.

Step-by-step explanation:

Given that , the lower of the class is 10 and the upper limit is 40.

We have to find the mid point of the class.

Lower limit = 10

Upper limit = 40

We know that,

Mid point = $\frac{lower limit + upper limit}{2}$

Therefore, midpoint = $\frac{40+10}{2} =\frac{50}{2}$ = 25.

Hence, the midpoint of the given class is 25.