If the lowest form of a fraction is a/b, (b≠0)ab, (b≠0) , then
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ab can be represented in a terminating decimal representation only if by multiplying both the numerator and denominator by some whole number n , you can get
ab=n×an×b=n×a10k
⟹n×b=10k
⟹n=10kb
⟹n=2k×5kb
Since n is a positive integer, 2 and/or 5 can be the only prime factors of b .
So we have our answer -
ab can be represented in a terminating decimal representation only if b=2p×5q , where p and q are non-negative integers, including zero.
Step-by-step explanation:
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