Physics, asked by keerthivasan1617, 4 months ago

If the magnification of -1 is to be produced with the

help of converging mirror, the object has to be

placed-

a) Between pole and focus

b) At the centre of curvature

c) Beyond the centre of curvature

d) At infinity ​


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Answers

Answered by MystícPhoeníx
122

Answer:

  • (b) Centre of Curvature is the required answer .

Explanation:

Here , the mirror used is Converging mirror . As we know that Concave mirror is converging in nature.

If the object is placed at centre of Curvature the image height is equal to object & negative sign show that the image is formed below the principal axis.

For More Information Refer to Attachment !!

Some Related Term !!

• Focal length :- The distance between the pole and the focus is called Focal length .

• It is denoted by f

• SI unit of Focal Length is Dioptre (D).

Relationship between Focal length and Radius of Curvature are

• f = R/2

where,

f is the focal length

R is the radius of Curvature

• Radius of Curvature :- The distance between the pole and the Centre of Curvature is called the radius of Curvature.

• Pole :- The centre of the spherical mirror is called its Pole .

Attachments:

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Answered by Anonymous
53

Answer:

Question :-

If the magnification of -1 is to be produced with the help of converging mirror, the object has to be placed

a) Between pole and focus

b) At the centre of curvature

c) Beyond the centre of curvature

d) At infinity

Answer :-

B) Centre of curvature

Explanation :-

Concave Mirror

Some characteristics

  • Light from a source converge at a point and reflect back from the reflecting surface of the mirror
  • The image can be either large or small and either virtual or real

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