Question

If the magnification of a lens has a positive value the image is
Real f
Virtual and erect 2f
Inverted 2f
None of these​

Answer 1

Answer:

ans

Explanation:

vertual and erect

Answer 2

Answer:

Correct option is B virtual and erect

Magnification= Image size/Object Size=hi/ho

According to new Cartesian sign convention, size of height of real and inverted image is considered negative and that of virtual and erect image is considered positive.

The heigh of the object, being erect is considered positive always.

So, for positive magnification, the ratio, mentioned above, will be positive. This implies that the image height will also be positive.

The image will be virtual and erect.

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