Question

If the magnitude of 2N and 3N is 4N . Find angle between 2N and 4N ?
( correct answer = brainliest + follow )

Answer 1

Answer:

if the magnitude of 2n and 3n

Answer 2

Answer:

given :- R(resultant) = 4N .

Formula :-

[ R² = A² + B² + 2AB cos Q(theta) ]

==> 4² = 2² + 3² + 2(2)(3) cos Q

==> cos Q = 1/4 .

==> Angle = Q = Cos ^- (1/4) ans .