If the magnitude of 2N and 3N is 4N . Find angle between 2N and 4N ?
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Answer:
if the magnitude of 2n and 3n
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Answer:
given :- R(resultant) = 4N .
Formula :-
[ R² = A² + B² + 2AB cos Q(theta) ]
==> 4² = 2² + 3² + 2(2)(3) cos Q
==> cos Q = 1/4 .
==> Angle = Q = Cos ^- (1/4) ans .
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