If the magnitude of displacement is numerically equal to
that of acceleration, then the time period is
(a) 1 second (b) π second
(c) 2π second (d) 4π second
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✪ Question
If the magnitude of displacement is numerically equal to that of acceleration, then the time period is
(a) 1 second (b) π second
(c) 2π second (d) 4π second
✪ Solution
(c) 2π seconds
✪ Explanation
ÿ = ω²y
⇒ω = 1
⇒4π²/T² = 1
⇒T² = 4π²
⇒T = 2π seconds
Answered by
16
ÿ = ω²y
⇒ω = 1
⇒4π²/T² = 1
⇒T² = 4π²
⇒T = 2π seconds
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