Physics, asked by nikhilgiri4414, 8 months ago

If the magnitude of displacement is numerically equal to
that of acceleration, then the time period is
(a) 1 second (b) π second
(c) 2π second (d) 4π second

Answers

Answered by CunningKing
0

✪ Question

If the magnitude of displacement is numerically equal to  that of acceleration, then the time period is

(a) 1 second (b) π second

(c) 2π second (d) 4π second

✪ Solution

(c) 2π seconds

✪ Explanation

ÿ = ω²y

⇒ω = 1

⇒4π²/T² = 1

⇒T² = 4π²

⇒T = 2π seconds

Answered by Anonymous
16

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ÿ = ω²y

⇒ω = 1

⇒4π²/T² = 1

⇒T² = 4π²

⇒T = 2π seconds

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