Question

If the magnitude of either of the forces forming

a couple is 40N and the perpendicular distance

between their lines of action is 1.5m, find the

magnitude of the torque​

Answer 1

Answer:

torque will be 60Nm.

Explanation:

Answer 2

Answer:

The magnitude of torque produced is 60 Nm.

Explanation:

The torque is defined as the cross product of force and the perpendicular distance from the action of force. Which is given as,

$\tau=r\times F$      (1)

Where,

τ=torque produced

r=perpendicular distance from the action of force

F=force acting on an object

From the question we have,

r=1.5m

F=40N

By substituting the values in equation (1) we get;

$\tau=1.5\times 40$

$\tau=60Nm$

Hence, the magnitude of torque produced is 60 Nm.