Physics, asked by jharachatp6kayx, 10 months ago

If the magnitude of either of the forces forming couple is 32 N and perpendicular distance between their lines of action is 2.0m , find the magnitude of torque.

Answers

Answered by nirman95
74

Answer:

Given:

Either of the forces forming a couple has a magnitude of 32 N.

Perpendicular distance between the forces = 2 m

To find:

Torque experienced by the object.

Concept:

Torque is often called the " moment of couple ". As it denotes the rotational analogue of force. In other words it represents the turning force experienced by the body .

Formulas used:

Torque = Magnitude of force × ⊥distance

Diagram:

Please refer to the attached photo to understand better.

Calculation:

Torque = Magnitude of force × ⊥distance

=> τ = 32 × 2

=> τ = 64 Nm.

Attachments:
Answered by Anonymous
32

Answer:

We know :

T = F × r sin Ф

or

Torque = Force × Perpendicular distance .

Given :

F = 32 N

Distance r = 2 m

Torque = 32 × 2 N m

Torque = 64 N m .

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