Question

If the magnitude of sum of two vectors is equal to the magnitude of difference of the two vector, the angle between these Vector is

Answer 1

Answer:

X=π/2

Explanation:

Let the vectors be A and B and the angle between them be X

then;

since |A+B|=|A-B|

=>  $\sqrt[]{A^{2}+B^{2}+2ABcosX}= \sqrt[]{A^{2}+B^{2}-2ABcosX}$

=> 4ABcosX=0

=> cos(X)=0

=> X=π/2

Hope this answer helped you :)