Question

If the magnitude of the vector products of two vectors | A x B | is â3 times the magnitude of their scalar product A . B then the angle between them is ............ . (A) Ï/2 (B) Ï/6 (C) Ï/3 (D) Ï/4

Answer 1

Explanation:

i hope this will help u thnkx

Answer 2

Answer:

Option (C) ic correct.

Explanation:

Since we know that the scalar product is given by,

$A.B = |A||B|cos\theta$..................(1)

we also know the vector product is given by,

$|A\times B|=|A||B|sin\theta$.................(2)

We had given that magnitude of the vector products of two vectors | A x B | is 3 times the magnitude of their scalar product A.B

$|A\times B| = 3A.B$

Divide (2) by (1) we get,

$\dfrac{1}{3} = Cot(\theta)$

So, option (C) ic correct.