Question

If the magnitude of two vectors are 4 and 6 and the
magnitude of their scalar product is 12 under root 2, then
the angle between these vectors, is
(1) 90°
(2) 45°
(3) 30°
(4) 60°​

Answer 1

Answer:

45°

Explanation:

Let,

• |A| = 4
• |B| = 6
• Angle between them = ∅

Scalar product (also called dot product) of two vectors A and B separated by angle ∅ is given as

• |A • B| = |A||B|Cos∅

It's given that |A • B| = 12√2

So,

12√2 = (4 × 6) × Cos∅

Cos∅ = 12√2 / (24)

Cos∅ = (√2) / 2

Cos∅ = (√2 / 2) × √2/√2

Cos∅ = 1/√2

Cos∅ = Cos45°

∅ = 45°

Answer 2

Answer:

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Explanation:

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