Question

if the magnitude of two vectors are 8 unit and 5 unit and the scalar product is zero the angle between the two vectors is.​

Answer 1

Given:

The magnitude of two vectors are 8 unit and 5 unit and the scalar product is zero.

To find:

Angle between the two vectors ?

Calculation:

Let the angle between the vectors be $\theta$.

Now, the scalar product (dot product) can be expressed as follows:

$\sf \therefore \: \vec{a} \: . \: \vec{b} = | \vec{a}| \times | \vec{b}| \times \cos( \theta)$

$\sf \implies \: 0= 8 \times 5 \times \cos( \theta)$

$\sf \implies \: \cos( \theta) = 0$

$\sf \implies \: \theta = {90}^{ \circ}$

So, angle between the vectors is 90°.

NOTE:

• Whenever question states that the scalar product between two vectors is zero it always means that the angle between the vectors will be 90°.

Answer 2

Answer:

90°

Explanation:

the angle b/w the two vector is zero

cos=0

90°