if the magnitude of vector A B and C are 3 4 and 5 minut and a + b equal to C then what is the angle between a and b
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Explanation:
Let
x
ˉ
=30 units
B
ˉ
=44 unit
c
ˉ
=5 units
A+B=C
′
squaring m both side
(A+B)
2
=C
2
=1
A
2
+B
2
+2ABcosθ=C
2
3
2
+4
2
+2×3×4cosθ=5
2
24cosθ=25−25
cosθ=0/2
cosθ=0
θ=cos
−1
(0)=90
o
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