Question

If the magnitude of vectors A bar B bar C bar are 12 5 13 units respectively and A bar+B bar is equals to C bar, the angle between vectors A bar and B bar

Answer 1

Answer:

90°

Explanation:

given:-

A bar =12

B bar= 5

C bar = 13

A/C A bar +B bar =C bar

now,

• |c bar|^2 = |A bar|^2 +|B bar|^2 + 2 |A bar|•|B bar| cos theta

• 13^2 = 12^2+5^2 + 2×12×5 cos theta

• 169= 144 + 25 +120 cos theta

• 169-169 = 120 cos theta

• 0= 120 cos theta

• cos theta=0/120

• cos theta =0

hence ,theta = 90°