If the magnitudes of the vectors A, B and C are 6, 8, 10 units respectively and if A + B = C, then what is the angle between A and B ?
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5
Answer:
angle 90°
c Resultant
C=A+B
|a|=6, |b|=8, |c|=10
c=√a^2+b^2+2abcosx
10=√6^2+8^2+2•6•8cosx
10=√36+64+96cosx
10=√100+96cosx
10^2=100+96cosx
100=100+96cosx
100-100=96cosx
0=96cosx
cosx=0/96
cosx=0
cosx=90°
I hope you understand
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