If the magnitudes of two vectors are 3 and 4 and their scalar product is 6, then find the angle between the two vectors.
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Answer:
60 degrees
Explanation:
As scalar product is 3*4*cos(theta)
which equals 12cos(theta)=6
implies cos(theta)=1/2 or
conversely (theta) or angle= cos inverse(1/2)
which equals 60 degrees
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